Wednesday, November 22, 2006

I

I = union_x say(I,!x)
I = U - union_x say (I,x)
please solve for I.

5 comments:

nice try said...

of course, trust(I,I) ~ 0

SVR said...
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SVR said...

U is undefined. Not familiar with the construct "say". :)

Obviously, some rare visitors aren't familiar with the conventions & language of the mmm-land. :P

nice try said...

U is universe
say --> is what it says .. "I am a dog" translates into say(I,dog)

madatadam said...

isnt I=\phi in ur construct or atleast it seems a pessimistic(negative?!) construct?
i thot
I = union_x say(I,x) && I = U - union_x say(I,!x) would be a better definition of I. Of course trust(I,I) ~ 0 still holds.